A thin convex lens 
(refractive index 
) is placed on a plane mirror 
. When a pin is placed at 
, such that 
, its real inverted image is formed at 
itself, as shown in figure. When a liquid of refractive index 
is put between the lens and the mirror, the pin has to be moved to 
. such that 
, to get its inverted real image at 
itself. The value of 
will be:
Text Solution
Verified by ExpertsB
For image to form at object itself, says must retrace their path back to object. Hence must incident on mirror normally.
Case 1: Object will be at focus of lens
Case 2: Retraction at 
surface:
retraction:
From (i) and (ii)
.
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